What is the surface area in square feet of a rectangular prism with dimensions of 2 feet by 3 feet by 4 feet as shown in the net?.Find the surface area for the given prism. Length: 41 ft Width: 32 ft Height: 49 ft 1. a solid with two parallel and congruent bases which solid has two bases that are triangles and three lateral surfaces that are rectangles a. How much greater is the surface area of the rectangular prism than the surface area of theġ.:Triangular Prism :Triangular Pyramid*** :Cone :Triangle 2) Name the solid according to it's description: The figure has two bases that are parallel congruent circles. 1) Identify the solid form by the given net.how much greater is the surface area of the rectangular prism the surface area of the cube? 5. find the surface area of the triangular prism. what is the surface area of the rectangular prism? 3. Rectangular prism Length: 17.2 Width: 3 Height: 5.5 283.8 m^2 292.4 m^2 325.4 m^2 407 m^2 I already found the surface area (325.4 m^2) and I'm using the formula for lateral surface area 2lh + 2wh. What is the lateral surface area of the prism?.The correct answer is none of the given options. Therefore, Dominique needs to buy 15 square feet of burlap to cover the whole flower box. Thus, the total surface area of the flower box is:Ģ x 2 square feet + 3 square feet + 6 square feet + 2 x 1 square foot = 15 square feet The area of the square with sides of 1 foot is: The area of the rectangle with dimensions 2 feet by 3 feet is: The area of the rectangle with dimensions 1 foot by 3 feet is: The area of the rectangle with dimensions 1 foot by 2 feet is: The squares each have sides with a length of 1 foot. The dimensions of the rectangles are 1 foot by 2 feet, 1 foot by 3 feet, and 2 feet by 3 feet. The flower box consists of three rectangles and two squares. To calculate the amount of burlap that Dominique needs to buy to cover the whole box, we need to calculate the surface area of the box. None of the given answer choices exactly matches with the computed answer, but the closest option to the correct answer is A) 182 units². Therefore, The surface area of the three-dimensional figure is 174 units². = 2 x (21 units² + 14 units² + 10 units²)įinally, we add up all the faces to get the total surface area of the figure: Since there are four trapezoidal faces, their total area is: (1/2) x base x height = (1/2) x 4 units x 5 units = 10 units² So, the area of each rectangle is:ģ units x 7 units = 21 units² or 2 units x 7 units = 14 units²Įach right triangle has a base of 4 units and a height of 5 units. The rectangles have dimensions of 3 units by 7 units or 2 units by 7 units. We can split each trapezoidal face into a rectangle and a right triangle, so that we can find their individual area and then add them up again to get the total area of the trapezoidal faces. Next, there are four trapezoidal faces on the sides of the figure.
Since there are two of these faces, their total area is: Each face has dimensions of 6 units by 7 units, so the area of each face is: Looking at the net, we can see that there are two identical rectangular faces on the top and bottom of the figure.
To compute the surface area of the three-dimensional figure using the given net, we need to find the area of each face and then add them up. Therefore, the surface area of the triangular prism is 260 cm2.Īnswer: None of the given options (the correct answer is 260 cm2) Total surface area = 2 x triangle area + 2 x rectangular area Therefore, the area of each rectangular face is:Īgain, there are two rectangular faces, so their total area is:įinally, we add up the areas of all the faces to get the total surface area of the triangular prism: The rectangular faces have base equal to 12 cm, height equal to 10 cm and length equal to 8 cm. There are two triangular faces, so their total area is: Thus, the area of each triangular face is: Using the net given we can see that the triangular faces are both right triangles with base and height both equal to 10 cm and hypotenuse equal to 13 cm.
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